40.5=(x^2)+x

Solution for 40.5=(x^2)+x equation:

40.5=(x^2)+x

We move all terms to the left:

40.5-((x^2)+x)=0

We get rid of parentheses

-x^2-x+40.5=0

We add all the numbers together, and all the variables

-1x^2-1x+40.5=0

a = -1; b = -1; c = +40.5;
Δ = b2-4ac
Δ = -12-4·(-1)·40.5
Δ = 163
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{163}}{2*-1}=\frac{1-\sqrt{163}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{163}}{2*-1}=\frac{1+\sqrt{163}}{-2}
$